2007-02-02 15:38:09 · 7 answers · asked by Sam Y 2 in Science & Mathematics ➔ Mathematics
x² -16.5x + 144
-(-16.5) ± √(-16.5)² - 4(1)(144) over 2(1)
= 16.5 ± √272.25 - 576 over 2
= 16.5 ± √-303.75 over 2
no solution because there is no real roots.. cause is negative..
2007-02-02 16:58:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
make it 2x^2 + 33x + 228, and then check for real solutions by using b^2 - 4ac ---> you get 1089-4(2)(228) = - 735 which results in a negative number, so there is no real solution to the polynomial and it cannot be factored
2007-02-02 15:46:42 · answer #2 · answered by dukebdevil93 2 · 0⤊ 0⤋
It's (x+4)(x-4) x^2-16 is an example of the difference of two squares.
2016-05-23 22:10:54 · answer #3 · answered by ? 4 · 0⤊ 0⤋
all quadratic expressions can be factored.
but not all can be if you require only reals.
in the present case, complex conjugates
are needed to factor
2007-02-02 16:14:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
no, the factors do not work out.
2007-02-02 15:54:55 · answer #5 · answered by matt p 2 · 0⤊ 0⤋
Sheesh, my head hurts just reading it, I can't imagine trying to solve it. :o)
2007-02-02 15:49:55 · answer #6 · answered by Speedy 6 · 0⤊ 0⤋
no, zeros come out as imaginary values
2007-02-02 15:40:17 · answer #7 · answered by One With No Name 2 · 0⤊ 0⤋