How would I find the domain of these functions?
g(x) =
2
/
x²+x-12
and...
g(x) =
1
/
√x+2
Thank you so much.
2007-02-02 15:23:09 · 3 answers · asked by alphaaxl 1 in Education & Reference ➔ Homework Help
x^2 + x - 12 <> 0
(x - 3)(x + 4) <> 0
x <> 3, x <> -4
so x can be anything but -4 or 3
x^1/2 + 2 <> 0
x^1/2 <> 2
x <> 4
so x can be anything but 4
2007-02-02 15:39:06 · answer #1 · answered by disposable_hero_too 6 · 0⤊ 0⤋
x^2 + x - 12 <> 0
(x - 3)(x + 4) <> 0
x <> 3, x <> -4
so x can be anything but -4 or 3
x^1/2 + 2 <> 0
x^1/2 <> 2
x <> 4
so x can be anything but 4
2007-02-02 21:40:29 · answer #2 · answered by Ivy 1 · 0⤊ 0⤋
you're really searching a triangle a^2+b^2=c^2 (pythagorum therom i have self assurance) if a=x and b=y then c= the dotted line First, sparkling up for b (x)(y)=area 8y=40 8 8y/8=40 8/8 y=6 SO a^2+b^2=c^2 8^2+6^2=c^2 sixty 4+32=c^2 one hundred=c^2 (sq. root of both part) 10=c
2016-12-03 09:29:43 · answer #3 · answered by Erika 4 · 0⤊ 0⤋