How do you find x in the problem ln(ln(x))=1?

Answer 1

take the antilog of each side, twice.
Take the antilog of something means raise e to the power of that something.
Since e^ln u = u for any u, no matter how complicated,
you do
e^(ln(ln(x))) = ln x = ... right hand side ...e^1 = e (anything to the 1 is itself)
This gets rid of one layer of ln, do it again
e^lnx = x = ,,, right hand side ... e^e
That may look strange but it's a perfectly good number. Since e is a little less than 3, e^e is a little less than 3^3 which is 27

Answer 2

ln(ln(x)=1

ln(x)=e and x=e^e

Answer 3

consider anti log both side
then
ln(x) = e
again take antilog
then
x= e^e