2007-02-02 14:56:11 · 3 answers · asked by awantwin2004 2 in Science & Mathematics ➔ Physics
If you are given the object's density and one other quantity, such as its mass, and some information about how it is floating (completely submerged, half out of the water, etc.) you can find the buoyant force exerted on it by the water.
Find the volume of the object D = m/V, then if the object is completely submerged that volume ALSO equals the volume of the water displaced. And the buoyant force is equal to the weight of the water displaced which is the density of water (.001 kg/ml)*Volume of the object*9.8 m/s/s.
2007-02-02 15:04:39 · answer #1 · answered by Dennis H 4 · 0⤊ 0⤋
If it is floating, the bouyant force = its weight... which also equals the weight of the fluid displaced when the object was introduced. So, fill the container to the brim, place the object in the liquid and weigh how much spills out.
2007-02-02 15:09:47 · answer #2 · answered by Richard S 6 · 1⤊ 0⤋
Net force acting on the floating object is zero.
2007-02-02 17:13:34 · answer #3 · answered by Pearlsawme 7 · 0⤊ 0⤋