2007-02-02 14:01:28 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First: multiply the 1st & 3rd coefficient to get "72." Find two numbers that give you "72" when multiplied & "18" (2nd/middle coefficient) when added/subtracted. The numbers are (6 & 12).
Sec: rewrite the expression with the new middle coefficients...
8x^2 + 6x + 12x + 9
Third: when you have 4 terms - group "like" terms & factor....
(8x^2 + 6x) + (12x + 9)
2x(4x + 3) + 3(4x + 3)
= (4x + 3 )(2x + 3)
2007-02-02 14:10:27 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
The factors of 8x^2+18x+9 are 4x+3 and 2x+3
2007-02-02 22:19:57 · answer #2 · answered by dennismeng90 6 · 0⤊ 0⤋
We need factors of 8•9 = 72 that add up to 18, and they are 6 and 12, so
8x² + 18x + 9 =
8x² + 6x + 12x + 9 =
2x( 4x + 3) + 3( 4x + 3) =
(2x + 3)( 4x + 3)
2007-02-02 22:10:16 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
Given expression
=8x^2+12x+6x+9
=4x(2x+3)+3(2x+3)
=(2x+3)(4x+3)
2007-02-02 22:04:40 · answer #4 · answered by alpha 7 · 0⤊ 1⤋
= 8x^2 + 12x +6x +9
= 4x ( 2x + 3 ) + 3 (2x + 3 )
= ( 2x + 3 ) ( 4X + 3 )
2007-02-02 22:04:33 · answer #5 · answered by sg 2 · 0⤊ 1⤋
You can do this with the quadratic equation, but I'll do it:
(4x+3)(2x+3)
2007-02-02 22:05:28 · answer #6 · answered by John T 6 · 0⤊ 1⤋
(4x + 3) (2x + 3)
2007-02-02 22:04:49 · answer #7 · answered by Anonymous · 0⤊ 1⤋