Please help me with this question.
I'm having trouble starting it.
2007-02-02 12:29:29 · 2 answers · asked by vicky p 1 in Science & Mathematics ➔ Physics
Heat needed = mass of water * specific heat of water (in appropriate units) * temperature change
If you use grams and calories, look up specific heat with these units accordingly
2007-02-02 12:36:04 · answer #1 · answered by Sir Richard 5 · 0⤊ 0⤋
Specific heat capacity is the key: c=Q/(m*(Tf-Ti) where c is that value, m is the mass and Tf-Ti is the temperature increment. The solving depends of your units. This is valid everytime you dont change the state (solid-liquid-gas) (hum..., gas in english really means gasoline, right?), where you need one more concept.
In the specific case of the water, every 1ºCelsius increased and 1g you need 1 calorie, so now you need (83-4.5)*50 =
3925 ``small´´ calories.
2007-02-02 12:43:52 · answer #2 · answered by topoyiyo149 1 · 0⤊ 0⤋