What is the 6th term in the expansion (3x + 2y)^7?

Answer 1

the answer is

6048(x^2)(y^5)

use the binomial theorem.

Answer 2

Remember, in an expansion of this kind there are eight terms because the powers for x and y range from zero to seven. The sixth term in the expansion is:

(7C5)*[(3x)^(7-5)]*[(2y)^5] = (21*3²*2^5)x²y^5 = 6048x²y^5

Answer 3

(7*3*2^6)xy^6=1344xy^6