y = 2x - 5 and y = 2x + 5
Both have the same slope, 2 and different intercepts.
They are parallel.
3x + y = 5 and -x + 3y = 6
They have slopes of -3 and 1/3 which are negative reciprocals.
They are perpendicular.
3x + y = 5 and x + y = 3
They have slopes of -3 and -1.
They are neither parallel or perpendicular.
2007-02-02 12:56:01
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answer #1
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answered by Northstar 7
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Finding a pair of parallel lines are easy! First, you find the slope (it usually is where the x is. So for y=8x+6, the 6 would be the y-intercept (where the point is on the y-axis) and the 8 would be the slope (the measure of how "steep" a line is)). If the slope of the equations are the same (for ex.y=2x-5 and y=2x+5), then the lines are parallel. For detecting perpendicular lines, the slopes are exactly opposite from each other (For example, y=2x-9, and y=-1/2x-9). For neither, both of the slopes are different numbers and sometimes, different signs.
I don't know much, since I am only an 8th Grader! :-(
2007-02-02 13:21:17
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answer #2
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answered by zswrs1 3
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y = 2x - 5 and y = 2x+5 are parallel, because both have slope of 2
3x + y = 5 and -x+3y = 6 are perpendicular, because putting in slope int form
y = -3x+5 and y=1/3x+2 slope of -3 and 1/3 negative reciprocals
3x+y=5 and x+y = 3
y = -3x+5 y = -x+3
Neither parallel or perpendicular.
2007-02-02 11:36:47
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answer #3
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answered by leo 6
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Finding and recognising parallel and perpendicular lines is easy.
THe form of your equations are y=mx+b (slope intercept form.)
m represents the slope of the line, so equations with the same number before x are parallel.
Equations where the slope of two lines are opposite reciprocals are perpendicular. Example: The opposite reciprocal of 2 is -1/2. The opposite reciprocal of -1/3 is 3.
Hope that helps! :)
2007-02-02 10:48:53
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answer #4
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answered by alicehodges 3
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