-- it must CONDITION or NOURISH your eyelashes.
-- it also must very EASY to come off.
no waterproof
2007-02-02 10:03:28 · 10 answers · asked by Anonymous in Beauty & Style ➔ Makeup
Bourjois Paris- Pump Up the Volume.
You could purchase the lash conditioner base coat seperately for $7.50 at sephora.com or the store.
2007-02-02 10:50:56 · answer #1 · answered by I _Know_ Thangs 3 · 0⤊ 0⤋
I think the best mascara is Maybelline, I have very long eyelashes, but I think Maybelline works very good, I use the Volum Express Mascara & the color is brownish black, I think it makes my eyelashes even longer, well that's the mascara I like.
GOOD LUCK...
2007-02-02 18:33:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I used to like the pink bottle with green top... Maybeline I think???
But I have very long, thick eyelashes so I prefer to use Pout now. It's not meant to do what all the other brands advertise. "Longer Thicker Lashes" on me looks like "Fuzzy Fat Caterpillars."
2007-02-02 18:06:56 · answer #3 · answered by misskate12001 6 · 0⤊ 0⤋
the best is M.A.C and it maybe exspensive but it has a lot and it is worth it so yah and you can maybe get a special package with 2 of them in there for a really good price so yahhh
2007-02-02 18:06:17 · answer #4 · answered by cailyn w 2 · 0⤊ 0⤋
I think Max Factor is cheap and nice and easy to wash off!! u should def try it.
2007-02-02 18:26:29 · answer #5 · answered by beebee32002 2 · 0⤊ 0⤋
Mary Kay of course!! It is great mascara.
2007-02-02 18:06:57 · answer #6 · answered by futureteacher0613 5 · 1⤊ 0⤋
oj then i must insist on kiss me mascara and kiss me rimel!Youll love it!!OMG your eyelashes will becaome stronger and longer trust mehttp://www.misikko.com/kiss-me-mascara.html
2007-02-02 18:09:20 · answer #7 · answered by Hey!! 1 · 0⤊ 0⤋
Mac X is awesome.
2007-02-02 18:06:39 · answer #8 · answered by yankeesfn02 1 · 0⤊ 0⤋
Rimmel has a new one with Lycra. I love it.
2007-02-02 18:06:34 · answer #9 · answered by chvyno1 2 · 0⤊ 0⤋
mac
2007-02-02 18:06:16 · answer #10 · answered by $0.02 3 · 0⤊ 0⤋