did i do this problem correctly?

0 ⤊

(3√3-√5)(√6+√3)=

3√18+3√9-30-15

ans:9√2+9-30-15?

2007-02-02 08:33:35 · 2 answers · asked by ,,,,,,, 2 in Science & Mathematics ➔ Mathematics

You seem to have misplaced a few radical signs, but everything else looks correct.

3√18+3√9-√30-√15

9√2+9-√30-√15

2007-02-02 08:51:04 · answer #1 · answered by mirramai 3 · 0⤊ 0⤋

=3sqrt18 +9 -sqrt30 -sqrt15

2007-02-02 16:56:18 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋