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solve the following equations:Xsquared-13X+42=0 and
Xsquared-8X-65=0

2007-02-02 08:21:39 · 8 answers · asked by jessys 1 in Science & Mathematics Mathematics

8 answers

1) x^2 - 13x + 42 = 0

To solve this, you have to ask yourself: what two numbers multiply to make 42 (the third constant term) and add to make -13 (the coefficient of x)? The answer to that is -6 and -7, so this factors as

(x - 6)(x - 7) = 0

In order for this to equal 0, x - 6 = 0 or x - 7 = 0. Solving these two equations, we get x = 6 or x = 7.

2) x^2 - 8x - 65 = 0

What two numbers multiply to make -65 and add to make -8? The answer to that is -13 and +5, so this factors as

(x - 13)(x + 5) = 0

Which means x = 13 or x = -5.

2007-02-02 08:26:33 · answer #1 · answered by Puggy 7 · 1 0

x^2-13x+42=0 = (x-7)(x-6) = x=7 & x=6
x^2-8x-65=0 = (x-13)(x+5) = x=13 & x= -5

thats easy all u have 2 do is get da factors 4 da third number and make sure u can get da 2nd number as plus or minus da way it is in da equations

2007-02-02 17:15:23 · answer #2 · answered by elektra 1 · 0 0

factoring
1st one
x^2 - 13 x + 42 = 0
to
(x - 7)(x - 6) = 0
so x = 7 or x = 6

and the second

x^2 - 8 x - 65 = 0
(x - 13)(x+5)

so x = 13 or x = -5

2007-02-02 16:28:28 · answer #3 · answered by dhaval70 2 · 0 0

use the quadratic formula x = { -b +/- sqrt(b^2-4ac)}/2a

x^2 -13x +42 =0
x = (13 +/- sqrt{13^2-4*42})/2
x = (13 +/- sqrt{1})/2
x=12/2 =6 and x=14/2=7

x^2-8x-65
x=(8 +/-sqrt{64+4*65})/2
x=(8 +/- sqrt{324})/2)
x=(8 +/- 18)/2
x=26/2 = 13 and x = 10/2 = 5

2007-02-02 16:50:56 · answer #4 · answered by bignose68 4 · 0 0

lol...

1st equation ~ x=7 , x=6
2nd equation ~ x=13 , -5

2007-02-02 16:32:55 · answer #5 · answered by uzairsml 1 · 0 0

Isn't that the point in homework?

If someone else does it for you, then you might as well quit school.

2007-02-02 16:24:30 · answer #6 · answered by superfunkmasta 4 · 1 0

do your own homework!!! its a friday and I dont do homework on fridays, especially not other peoples.

2007-02-02 16:29:02 · answer #7 · answered by flutterflie04 5 · 0 0

i would say go to http://www.studybuddy.com . Its the best!

2007-02-02 16:29:27 · answer #8 · answered by The Kwl Kid 3 · 0 0

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