the boxster is essentially the cabrio caymen. The "caymen does have a very slightly different platform though (its closer to a 911 with its engine/tranny switched around the rear axel)."
No, no, no. The platform is the same, the structure of the cars aren't.
There probably won't be a Cayman Cabrio, and the Boxster isn't a Cabrio unless you get the Cab version. The Boxster is a roadster, in other words, it had no full-time top when it came out. The top would usually be down more than up, unless you want it up. Picture it though, a Cayman Cabriolet would look EXACTLY like a Boxster, since the Caymans structure is different towards the top, due to supporting the car, why would you make another Boxster?
By the way. The structures are different than you think. The Boxster actually weighs MORE than the Cayman, because the Cayman is more like a regular car, hence hardtop, they don't need more support in the lower half of the car, like the Boxster with no top. Make any sense? If you're still not sure, I recommend TheAutobahn.com, a great place to learn and discuss Porsches.
2007-02-06 07:01:24
·
answer #1
·
answered by 1coolkid 2
·
0⤊
0⤋
There would be no need for a cabrio version as the porsche cayman s is the hardtop version of the porsche boxter.
2007-02-02 10:50:23
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
I would have to agree with kimmy, the Cayman and Cayman S are simply hardtop versions of the Boxster model.
2007-02-04 05:49:56
·
answer #3
·
answered by David 2
·
0⤊
0⤋
the boxster is essentially the cabrio caymen. The caymen does have a very slightly different platform though (its closer to a 911 with its engine/tranny switched around the rear axel).
but if you want a cabrio for that price, you can get a 996 turbo cab for around the same price....
2007-02-04 15:12:10
·
answer #4
·
answered by Kyle M 6
·
0⤊
1⤋
that would be called a Boxster S.
2007-02-05 05:59:51
·
answer #5
·
answered by Know what you mean 1
·
0⤊
0⤋
It's called a .....Boxster...sheeze
2007-02-05 10:11:11
·
answer #6
·
answered by LovePinkPuffies 3
·
0⤊
0⤋