I am having trouble answering this question: http://www.actstudent.org/sampletest/test4/math4/mcorr9.html. I have to find what x is.
I see the answer, but I am confused how to arrive at it. Can someone please give a more detailed explanation of how to get the answer. Thanks.
2007-02-02 07:33:25 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
you have a broken link on your hyperlink. I can give you an example. Use this equation a^2 + b^2 = c^2
The slope part of the triange would be "c"
The hight part of the triange would be "b"
The base part of the triange would be "a"
This works on all 90° triangles.
If for example c (the slope) = 5
___________a (the base) = 3
to find b, use this...
a^2 + b^2 = c^2
(plug in 3 for a and 5 for c)
3^2 + b^2 = 5^2
(find the square root of 3 and 5)
9 + b^2 = 25
(subtract 9 from both sides of the equal sign)
b^2 = 16
(Square both sides)
b = 4
I hope this was helpful to you.
2007-02-02 07:44:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The ration of sides of a 30° - 60°- 90° triangle is 1:â3:2
2007-02-02 15:58:53 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
Since 30:60:90 triangles are common, the ratios between the lengths of the sides are usually memorized for lame tests like the ACT and SAT.
In a 30:60:90 triangle, the sides are related by 1:sqrt(3):2
Meaning, the short leg is half the length of the hypotenuse and the long leg is the length of the short leg times the square root of 3.
Of course if you are using a calculator, you can always use the nifty trig functions.
Edit: the link is not working because there is a period on the end of it.
2007-02-02 15:41:59 · answer #3 · answered by wdmc 4 · 0⤊ 0⤋
Your link is not working, but an important fact about 30-60-90 triangles is that their sides are in the ratio 1:sqrt(3):2, so if you know the length of one side, you can easily find the other two.
2007-02-02 15:38:10 · answer #4 · answered by Chris S 5 · 0⤊ 0⤋
If you have only the angles there are infinite triangles all similar.
With those angles the triangle is half of an equilateral triangle divided by one height.
2007-02-02 15:48:53 · answer #5 · answered by santmann2002 7 · 0⤊ 0⤋
website is not working, plus i dont want to give away the answer, just the clue - since one side is 90deg, try using sin & cos for the sides.
2007-02-02 15:36:53 · answer #6 · answered by pksk212 3 · 0⤊ 1⤋
Can't get to the page.
Would be willing to help.
2007-02-02 15:37:22 · answer #7 · answered by Amber 2 · 0⤊ 0⤋