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I have to complete this problem for math and Im very confued by it, could someone please figure it out and explain it?

2007-02-02 06:32:54 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

Looks like you are missing parentheses. I think you mean:
(x^2+3x)/(2x+6)
(x(x+3))/(2(x+3)
x/2

2007-02-02 06:39:15 · answer #1 · answered by KingGeorge 5 · 0 0

If the expression is a single fraction, then factor the numerator & denominator:
x² + 3x = x(x + 3)
2x + 6 = 2(x + 3)
So,
(x² + 3x) / (2x + 6) =
[x(x + 3)] / [2(x + 3)] =
(x / 2).

2007-02-02 14:45:56 · answer #2 · answered by S. B. 6 · 0 0

I'm assuming you mean
(x^2+3x)/(2x+6)

This can be solved using polynomial division.
Find something that you could multiply to (2x+6) so that you get something that starts with x^2. That's going to be (1/2)x so (1/2)x(2x+6)=x^2+3x
we got lucky on this one normally you would subtract this result to eliminate the x^2 term and do it again for your remainder.
But we got it in the first step.
So (x^2+3x)/(2x+6)=(1/2)x

2007-02-02 14:44:40 · answer #3 · answered by snilubez 2 · 0 0

I assume you meant to write the problem like this:

(x² + 3x)/(2x + 6)

Simplify:

x(x + 3)/(2(x + 3))

Cancel out the x + 3 on top and bottom, and you have:

x/2, where x ≠ -3

2007-02-02 14:38:14 · answer #4 · answered by Dave 6 · 0 0

if it is (x^2 + 3x)/(2x+6), then you can simplify it to
x(x+3) / (2)(x+3) , and the (x+3)'s cancel out to give you
x/2

2007-02-02 15:09:13 · answer #5 · answered by Jen G 2 · 0 0

x(x+3)
-------
2(x+3)

x+3 cancel out

answer x/2

2007-02-02 15:10:26 · answer #6 · answered by Dave aka Spider Monkey 7 · 0 0

x^2+3x/(2x+6)=(x^2(2x+6)+3x)/(2x+6)=(2x^3+6x^2+3x)/(2x+6)

2007-02-02 14:39:26 · answer #7 · answered by Esmaeil H 2 · 0 0

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