I am given side AB = 20 and side BC = 16
Side AB is the hypotenuse
I need to find side AC which forms the right angle
The questions are What is the length of side AC
then find the perimeter and the area of the right triangle.
Help please
2007-02-02 06:27:53 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
AC=sqrt(400-256)=sqrt(144)=12
area=12*16/2=96 and perimeter is 12+16+20=48
2007-02-02 06:33:30 · answer #1 · answered by Esmaeil H 2 · 0⤊ 0⤋
The square of the hypotenuse = the sum of the squares of the sides of the right triangle. Let AC = x.
20² = 16² + x²
x² = 400 - 256
x² = 144 Since the square root of 144 is 12,
x = 12
Since the length of side AC is 12, the right triangle has a perimeter of 12 + 16 + 20 = 48.
The area of the rectangle is 12x 16 = 192 units². Therefore, the right triangle is ½ of 192 or 96 units².
2007-02-02 07:07:40 · answer #2 · answered by Marv 2 · 0⤊ 0⤋
Let AC = x
AB² = BC² + AC²
20² = 16² + x²
x² = 20² - 16² = 400 - 256 = 144
x = 12
AC = 12
Perimeter is 12 + 16 + 20 = 48
Area = 1/2 x 12 x 16 = 96
2007-02-02 06:50:16 · answer #3 · answered by Como 7 · 0⤊ 0⤋
AB² = AC² + BC²
20² = AC² + 16²
400 = AC² + 256
AC² = 400 - 256 = 144
AC = 12
So, the perimeter is 48, and the area is ½(AC)(BC) = ½(12)(16) = 96
2007-02-02 06:36:30 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
Side AC is 12 units.
The perimeter is 48 units, and the area is 120 square units.
2007-02-02 06:40:43 · answer #5 · answered by ZZ 4 · 0⤊ 0⤋
The hypotenuse squared/line BC squared = line AC squared.
Take line AC squared and find the square root. There you go.
You're using Pythagorus, you know?
2007-02-02 06:34:04 · answer #6 · answered by Deconstitutionalization 4 · 0⤊ 0⤋
using pythagoras therom (a2+b2=c2) you can find out that the length is 12cm
and the perimeter is 48cm
2007-02-02 06:44:45 · answer #7 · answered by Anonymous · 0⤊ 0⤋