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I am not sure if it is possible to do, but I was wondering if it is. A ball at rest begins rolling down a ramp at uniform acceleration. In the second 5 seconds (time 5

2007-02-02 05:24:07 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Assuming no friction or air resistance, just use the falling body formula: 32 feet per second squared. (Or 32 feet per second per second)

2007-02-02 05:28:00 · answer #1 · answered by Stuart 7 · 0 0

In the 1st 5 seconds it reached a velocity
V = a*t = 5*a

For the 2nd 5 seconds, call the above velocity Vo, because it's the original velocity in the equation
x = Vo*t + (1/2)*a*t^2
100 m = 5*a*5 + (1/2)*a*5^2
100 m = 25*a + 12.5*a
Solve for a and plug a into the 1st equation.

2007-02-02 10:23:08 · answer #2 · answered by sojsail 7 · 0 0

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