two guys will ask me out. will this also be true for my 5 other Aries friends??
are horoscopes even true??
2007-02-02 04:52:04 · 9 answers · asked by ♀proud american♀ 2 in Entertainment & Music ➔ Horoscopes
My horoscope has been right maybe once. That's it. The information in them is usually very vague.
Don't rely on horscopes. Unless your horoscope has been right every time in the past (if so, let me know, because I would love one that's actually true) I wouldn't count on it
Have a Happy Valentine's Day!
2007-02-02 05:10:13 · answer #1 · answered by Carolinii 2 · 2⤊ 0⤋
I'm Aries and I hope that I don't get the same message!
My wife would wonder what the heck is going on if a couple of guys ask me out!
So, for my sake, let's hope that horoscopes are NOT true!
2007-02-02 13:26:09 · answer #2 · answered by docscholl 6 · 1⤊ 0⤋
horoscopes are complete bullpoop...........but if you want somebody to ask you out on Valentines Day just come on Y!A........im an Aries too maybe ill ask you out
2007-02-02 12:56:05 · answer #3 · answered by SpinKick 6 · 2⤊ 0⤋
who knows, that seems a little to specific, however, my horoscope today is right one the money....it said I need to move on from a broken relationship...and I do, and am! Wait and see.
2007-02-02 13:00:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Aries rule; why don't YOU ask two guys out? Why wait?
2007-02-02 13:05:18 · answer #5 · answered by rla26368 3 · 0⤊ 1⤋
I'm an Aries too...uh oh...what will my husband think? :s
Hope those two guys can run fast.
2007-02-02 13:02:23 · answer #6 · answered by anonymous lucy 3 · 1⤊ 0⤋
wow, i am also Aries... i better stay out of San Francisco.
2007-02-02 12:59:40 · answer #7 · answered by Anonymous · 0⤊ 0⤋
probably not......depends who is doing the horoscope for you..
it is best if you get your OWN chart done for more accurate readings....
www.astralabe.com birthchart.....(free_)
2007-02-02 18:03:01 · answer #8 · answered by STARZ 5 · 0⤊ 0⤋
Many are not,& rising signs are important too
2007-02-04 01:43:50 · answer #9 · answered by ? 3 · 0⤊ 0⤋