Ahmed was traveling by a train (X). The train was going 45 Km per hour. Suddenly, another train (Y) was passing in the opposite way with a speed of 36 Km per hour. Y train took 6 seconds to pass through Ahmed’s train.
What was the length of the opposite train (Y)?
2007-02-02 03:42:31 · 5 answers · asked by Rajeev N 1 in Science & Mathematics ➔ Mathematics
45+36 = 81 kM/hr = .0225Km/sec = .135Km/6sec = 135Meters
2007-02-02 03:49:55 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
Since they're running in opposite directions, this would be the same problem if one train was still and the other was going 45+36 = 81 km/h.
But for one train to completely "pass through" another train, I would think that the on-coming train Y first has to come up to where the two heads meet, then pass along until the two tail ends of the train meet. So the total passing distance would be the length of the two trains combined. That value is obviously going to change depending on how long BOTH trains are. I'll suppose then that we're measuring train Y passing from head to tail past Ahmed's seat on train X. In that case the passing distance would be the length of the train.
Speed = distance / time, so the distance the front of the train travels in 6 seconds (which should be the length of the train) is (81 km/h) * (6/3600 hour) = 0.135 km, or 135 meters.
2007-02-02 13:31:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
therelative speed of theY train=81 kmph
=81*5/18 mps
distance=speed*time
=81*5*6/18m
=135 m
length of Ahmed's train=135 m
2007-02-02 11:46:44 · answer #3 · answered by raj 7 · 0⤊ 0⤋
The difference in speed is 81 km/hour.
This is 81,000 meters per hour.
This is 22.5 meters per second.
22.5 x 6 = 135 meters.
That's a really short train.
2007-02-02 11:48:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Use the method of R,T,D
Rate, Time , Distance.... Hope i gave you a head start but there is no way im giving you the answer...
Good Luck nad
Nice TRy
2007-02-02 11:47:59 · answer #5 · answered by musclovr456 2 · 0⤊ 0⤋