2007-02-02 03:06:38 · 13 answers · asked by ohsbabygirl22 1 in Science & Mathematics ➔ Mathematics
Please be specific. Do you mean: 3x + 5 = x - 17
Or, 3x + 5 = x + 17? I'll solve both equations.
1. 3x + 5 = x - 17
First: subtract "5" from both sides (when you move a term to the opposite side, always use the opposite sign)...
3x + 5 - 5 = x - 17 - 5
3x = x - 22
Sec: subtract "x" on one side...
3x - x = x - x - 22
2x = - 22
Third: isolate "x" on one side --- divide both terms by "2"...
2x/2 = - 22/2
x = -11
2. 3x + 5 = x + 17
First: subtract "5" from both sides...
3x + 5 - 5 = x + 17 - 5
3x = x + 12
Sec: subtract "x" from both sides...
3x - x = x - x + 12
2x = 12
Third: isolate "x" on one side --- divide both terms by "12"...
2x/2 = 12/2
x = 6
2007-02-02 04:23:19 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
There are a couple of right answers here depending on whether your original question was actually worded right. In reality there should not be 2 = signs in a single equation.
If the question was 3x + 5 = ? and x = 17 then 56 is right
If question was 3x + 5 = 17 then x = 4 is correct
3x + 5 = x = 17 is nonsense algebra.
2007-02-02 03:20:34 · answer #2 · answered by PuckDat 7 · 1⤊ 0⤋
This is an impossible statement. If x=17, then 3(17)+5=56, so 56=17=17 is a false statement.
If you are trying to say 3x+5=17, then subtract 5 from both sides to get:
3x=12, then divide both sides by 3, so:
x=4
2007-02-02 03:15:10 · answer #3 · answered by dennisjohns23 3 · 1⤊ 1⤋
All you do is do away with the brackets and simplify the equation: sixty 4 = 3x - 11 + 2x -2 sixty 4 = 3x +2x - 11 - 2 sixty 4 = 5x - 13 Now, rearrange the equation so which you have coefficients on one area (something that for the period of basic terms has a huge determination) and variables on the different (x is a variable). yet in a distinctive way of observing that is to function 13 to the two factors of the equation so which you're able to do away with the -13 on the suited area. sixty 4 + 13 = 5x - 13 + 13 seventy seven = 5x x = seventy seven/5
2016-11-02 03:19:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
This equation is improbable.Please check up again and send the right one.It may be 3x+5=x+17 or 3x+5=x-17or it may be 3x+5=17
2007-02-02 03:17:04 · answer #5 · answered by alpha 7 · 0⤊ 0⤋
3x+5=17
3x=17-5
3x=12
x=4
2007-02-06 02:58:48 · answer #6 · answered by fadiga 2 · 0⤊ 0⤋
Simple as pie.
3x+5=x=17..
You need to subtract the (x) and place it on the left side of the problem.
So it's not 2x+5=17.
Then you have to subtract 5 to get it onto the right side of the problem.
So your problem will be 2x=12.
Finally divid 2 by 12 which equals 6
so there for x=6
let me know if you need any other help i'm
in alg, two and trig.
2007-02-02 03:16:55 · answer #7 · answered by Hello there. 4 · 0⤊ 2⤋
3x+5=17
3x=17-5
3x=12
x=4
2007-02-02 03:15:37 · answer #8 · answered by Princess Shai 3 · 0⤊ 1⤋
Well x is equal to 17, so just plug in 17 for x.
3(17)+5
2007-02-02 03:11:31 · answer #9 · answered by Anonymous · 0⤊ 3⤋
Try a graphing calculator.
It says x is equal to 17, so wouldn't it be 3(17)+5?
2007-02-02 03:14:36 · answer #10 · answered by Ema Nova 4 · 0⤊ 2⤋