Find the antiderivative of (1/2x^4-3x^-2-3/4) in the intervals of 1 and 5?

Answer 1

The antidervivative is the integral of the function

I(1/2x^4 - 3x^-2 - 3/4) = 1/10 x^5 - 3/4 x + 3/x

I(5) - I(1) = 307

Answer 2

Assume that question being asked is:-

I = ∫ (1/2) x^4 - 3 X^(-2) - 3/4 dx between limits of 1 and 5

I = (1/10) x^5 + 3/x - (3/4)x between limits of 1 and 5

= (1/10) 5^5 + 3/5 - (3/4) x 5 - (1/10 + 3 - 3/4)

= 312.5 + 3/5 - 15/4 - 3 - (13/20)

= 312.5 + 0.6 - 3.75 - 3 - 0.65

= 306

Conclusion
This looks to be a nasty problem on account of nature of numbers involved.

Answer 3

(1/10)x^5+3x^(-1)-2.75x Now just evaluate this for the boundary that you have set.