What is the average rate of production of I2 in mmole/min ?

Question

2 HI(g) ----> H2(g) + I2(g)


100.0 mmoles of HI are initially in a 1.00 L container at 800 K After 400.0 seconds the concentration reduces to 0.0200 M.


What is the average rate of production of I2 in mmole / min ?

Answer 1

0.0200M =20mM

after 400 sec = 400/60 = 20/3 minutes, the concentration has reduced from 100 to 20 mM
so the reduction was 100-20 = 80mM in 20/3 min so by minute 80/(20/3) = 12mM/min

if you look the equation you see that 2HI---> I2

so the production of I2 is equal to dreduction of HI divided by 2

AND so Production of I2 = 6 mM/minute