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The straight lines kx = 4y + 5 and (2k + 2)x = 7- 6y are parallel. Find k.

2007-02-01 23:47:16 · 3 answers · asked by iqnabeel 1 in Science & Mathematics Mathematics

3 answers

Write both as y=mx+n where m is the slope
y=k/4 x -5/4

y= -(k+1)/3 x +7/6 Both slopes must be equal so

k/4=-(k+1)/3====> 3k = -4k-4 7k=-4 k= - 4/7

2007-02-01 23:59:40 · answer #1 · answered by santmann2002 7 · 0 0

if they rparallel=slopes r equal
kx=4y+5
kx-5=4y slope=k/4

//ly(2k+2)x=7-6y
2kx+2x-7=-6y
slope=2k+2/-6 -3k=4k+4 *k=-4/7

2007-02-02 08:11:28 · answer #2 · answered by Anonymous · 0 0

m1=k/4 and m2=(2k+2)/(-6)

we know m1=m2 thus k/4=(2k+2)/(-6) => -6k=8k+8 then

-14k=8 => k=8/(-14)=-4/7

2007-02-02 08:22:21 · answer #3 · answered by Esmaeil H 2 · 0 0

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