Let the two nos. be x & y , such that x>y.
Then, according to question,
x+y=60
&, x-y=24
Adding the two equations, we get,
2x=84
so, x=42
Therefore, 42-y=24, which implies, y=18
So, the two numbers are 42 & 18.
2007-02-01 23:46:01
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answer #1
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answered by Kristada 2
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There are several ways to solve this; here is the way I find least confusing.
Let x be the first number, and y be the second number. Now we have
x + y = 60 and
x - y = 24
Solve one of the equations for x (I'll choose the second equation)
x - y = 24
x = 24 + y
x = y + 24
Now substitute this "value" of x (y + 24) into the first equation like so:
y + 24 + y = 60
2y + 24 = 60
2y = 60 - 24
2y = 36
y = 36/2
y = 18
Now put this value of y back into where we started
x -18 = 24
x = 24 + 18
x = 42
Now check the results 42 + 18 = 60 and 42 - 18 = 24.
HTH
Charles
2007-02-02 09:17:45
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answer #2
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answered by Charles 6
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a + b = 60
a - b= 24
2a = 84
=> a = 42
=> b = 18 .
2007-02-02 07:46:55
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answer #3
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answered by Isme M 2
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it would be 42 and 18,for the sum of these numbers is 60 and their difference is 24....
2007-02-02 07:45:34
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answer #4
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answered by Anonymous
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x + y = 60
x - y = 24
Solve for x or y in one of the equations and plug that into the other equation. I solved for x in the 2nd equation to get x = y + 24. I then plugged that into the original to get (y + 24) + y = 60. Solving for y I got y = 18. Plug this back into one of the equations and get x = 42.
2007-02-02 07:47:40
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answer #5
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answered by Scottee25 4
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18 and 42
2007-02-02 07:44:27
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answer #6
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answered by lizbiz707 3
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