(help) Tnx
2007-02-01 21:07:00 · 3 answers · asked by HeLP2007 1 in Science & Mathematics ➔ Chemistry
The single bonds (and one of the bond in the triple bond) in C2H2 are counted as sigma. The second and third (double and triple) bonds are Pi bonds.
Drew a Pic for you so you can see it more clearly. I hope this helps. Cheers.
http://server6.theimagehosting.com/image.php?img=bonds.ac1.JPG&public_view=1&album=0&fullsize=1
2007-02-01 21:38:16 · answer #1 · answered by †ђ!ηK †αηK² 6 · 1⤊ 0⤋
C2H2 has Three sigma bounds 2 between respectively one C and one H. Between the carbons there is a triple bound which is composed of one sigma bound and two pi bounds
so you have in the molecule 3 sigma bounds
The 2 pi bounds are perpendicular and cannot hybridize
2007-02-02 05:21:05 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
sigma--3
pi--2
2007-02-02 05:46:24 · answer #3 · answered by shark 2 · 0⤊ 0⤋