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2007-02-01 21:05:26 · 4 answers · asked by HeLP2007 1 in Science & Mathematics Chemistry

4 answers

S in the SO2 is SP2 hybridization.

Im drawing a pic for you just a sec.

Here ya go:
http://server6.theimagehosting.com/image.php?img=res.eeb.JPG&public_view=1&album=0&fullsize=1

2007-02-01 21:20:25 · answer #1 · answered by †ђ!ηK †αηK² 6 · 1 0

As you know the electronic configuration of S is 3s2 3P4. One electron, from p orbital , excites in to d orbital. Now in the valency shell of S there is one electron pair in 3S orbital, three unpaired electrons in three 3p orbitals and also an unpaired electron in 3d orbital.The 3s orbital and two 3p orbitals undergo hybridization to form three Sp2 orbitals. Among these one Sp2 orbital is already filled with an electron pair and this pair doesnot participate in chemical bonding which is called as lone pair of electrons. The remain two Sp2 orbitals form two sigma bonds with p orbitals of oxygen atoms {2s2 2p4 in which oxygen contains two half filled 2p orbitals which participate in bond formation}. The remain hybridized half filled p and d orbitals of S form pi bonds with p orbitals of oxygen atoms.

So hybridization of S in SO2 is Sp2 but because of lone pair of electrons the geometry of the molecule is angular.

2007-02-02 05:45:23 · answer #2 · answered by manidhar 2 · 0 0

I have a very interesting link

It seems that the covalent bound between the sulfur and the oxygen are individualized with no hybridization

2007-02-01 21:29:34 · answer #3 · answered by maussy 7 · 0 0

sp2

2007-02-01 21:49:01 · answer #4 · answered by Anonymous · 0 0

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