ABC is a triangle with base AB. D is a point on AB such that AB = 5 cm and DB=3.What is the ratio of the area?

Question

of triangle ADC to the area of triangle ABC ????

Answer 1

3:5.... Just draw ABC, and draw ADC inside of it putting point D in the line AB like the problem says... the height will be the same for both triangles and you will always have to multiple for the same height to get both areas... if that's true then, the ratio is just a matter of bases.... 3 and 5.... the ratio is 3:5

Answer 2

Let perpendicular height = h cm
Area of Δ ABC = (1/2) x 5 x h cm ²
Area of Δ ADC = (1/2) x 3 x h cm ²
Area Δ ADC : Area Δ ABC = 3 : 5

Answer 3

Area ADC:AreaABC::2:5

Answer 4

C' is the projection of C to the base
so, both the height of the triangle (ADC and ABC) = CC'

AD=AB-BD
=2
area ADC = (AD*CC')/2
= (2*CC')/2
= CC'

area ABC = (AB*CC')/2
= (5*CC')/2
= 5CC'/2

areaADC : areaABC
=CC' : 5CC'/2
= 2 : 5

Answer 5

the answer is 13.5 In words: The triangle BDE is a factor smaller than ABC. And we know that BD is 2 units long and BA is (2+7=) 9 units long. That means that BD is 4.5 times smaller than BA therefore DE must be 4.5 times smaller than AC. It follows then that AC is 3x4.5= 13.5 units long. In symbols: Let u define units of length: BD = 2 u BA = 9 u BA/BD = AC/DE => 9/2 = AC/3 => AC = 3 x 4.5 = 13.5 u

Answer 6

Both triangles have a portion of the same base and both have the same height.

Area ΔA = ½bh

Area ΔABC = ½bh = ½*5h = 5h/2
Area ΔADC = ½bh = ½*3h = 3h/2

Area ΔADC/Area ΔABC = (3h/2)(5h/2) = 3/5

Answer 7

I also asked this same question so many times, and haven't gotten a proper answer

Answer 8

Loved this question

Answer 9

7.5sq. cm:7.5sq. cm