x/[(2x^0)^0]?

Question

I'm trying to help my brother w his homework. Is the answer x/4?

thanks people;)

Answer 1

if any number has a power 0
then the number directly becomes 1

2^0 = 1
7^0 = 1
x^0 = 1

therefore
x/[(2x^0)^0]

x/[1^0]

x/1 = x

simple...!!!

Answer 2

I may be totally wrong. But 10^2=100, 10^1=10, 10^0=1

Following the above which is easy to prove, your problem seems to say first, (2 * X^0) that would become 2 * 1 according to the above line. Next you have what became (2)^0 which also equals 1. ( all of this supposes that X > 0, if X = 0 then the equation would crash and burn)

For that reason, if your problem is correctly stated, the result of your equation is: X/1 =X.

For the proof that 10^0 = 1 you only need to know that 10^1= 10 and that 10^(-1)= 1/(10^1) then you may say 10/10 = 10^(1 -1) = 10^0 = 1

If I am wrong let me know. If you mis-stated the problem, try again.

Answer 3

2x^0 is 2, but 2^0 = 1, so the answer is x.

Answer 4

x/ [(2x^0)^0]
x/ [1]
x


anything to the 0th power is always 1 (ex. x^0 = 1 , 5^0 = 1)

Answer 5

No. x/((2x^0)^0)=x/(2*1)^0=x/1=x

for any a not equal to zero
a^0=1

Answer 6

Hi Kai - you R a student of biology.

In this question, you seemed excited by the (x^0)^0

Everyone told You that it is = 1

No one above have shown you why x^0 = 1

Let me show:

x^0 = {x}^(1-1) = (x^1) * (x^-1)
= (x) * (1/ x) = x / x = 1

Anything to the power zero is ONE.

rest is simple.

Answer 7

x/[(2x^0)^0] = x/[(2*1)^0] = x/[2^0] = x/1 = x

Answer 8

x/[(2x^0)^0]=
=x/[(2*1)^0]=
=x/(2^0)=
=x/1=
=x

here, x:R, x^0 is always 1.

Answer 9

answer is x


recall that anything raised to the power of zero is equal to one
x/[(2x^0)^0]
x/[(2*1)^0]
x/[(2)^0]
x/[1]
x

Answer 10

x/[(2x^0)^0]
= x/[(2*1)^0]
=x/(2^0)
=x/1
=x
since any no. raised to power 0 is 1