A fishtank has a rectangular base width 2 feet and length 4 feet, and rectangular sides of height 3 feet. If the tank is filled with water weighing 62.5 lb/ft^3, find the work required to pump all the water over the top of the thank.
Now the answer is 2250 ft-lb.....but I need to set this up using an integral, and so far I know I only know I'm finding the integral from 0 to 3 of (3-y)(62.5 times some equation for x) ... can anybody tell me what the equation for x would be and why?
2007-02-01 17:26:58 · 2 answers · asked by untitledonald 2 in Science & Mathematics ➔ Mathematics
Weight of the water at any particular depth
= 62.5 *2*4*dh = 500 dh
Work required to pump that weight of water from a depth h
500 * h * dh
Total work = Integral from 0 to 3 of (500 *h * dh) = 2250 ft-lb
2007-02-01 17:55:04 · answer #1 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
artwork = tension cases distance =375/(x^3 + 3.75x) cases x % a step length ie .01 meter evaluate 375x/(x^3 + 3.75x) for x =15 it is the commencing up element that would desire to be subtracted from finished then evaluate 375x/(x^3 + 3.75x) for x= 15+ step length ie 15.01 save including 0.01 to unique step length till 30 meters is reached. finished all outcomes - result at x=15 = finished artwork carried out . step length impacts accuracy. .01 grew to become into chosen for illustrative applications
2016-09-28 07:39:35 · answer #2 · answered by ? 4 · 0⤊ 0⤋