Okay, now I'm having problems with finding the square roots of fractions...and not fractions such as 81/144, but some such as 1/6...please...can you help?
2007-02-01 17:16:21 · 4 answers · asked by RachelDeeJay 2 in Science & Mathematics ➔ Mathematics
ex 1/6 in solving for the square roots of such fraction which both numerator and denominator not a perfect square you should multiply a certain square root which when you multiply to the denominator gives a perfect square...so the square root of 1/6 must be multiplied with square root of 6 to cancel out the radical sign below this is called as rationalizing so the result is square root of 6 over square root of 36 which we know 36 is a perfect square so we can factor out it to become 6 because 6 tomes 6 is 36..so the answer is square root of 6 over 6 since square root of 6 is not a perfect square it stay as it is
2007-02-01 17:45:44 · answer #1 · answered by Maricris D 1 · 0⤊ 0⤋
The square root of a fraction is the square root of the numerator over (divided by) the square root of the denominator.
The numerator is the number on top.
The denominator is the number on the bottom.
2007-02-02 01:29:14 · answer #2 · answered by J C 5 · 0⤊ 0⤋
IE. ___ _ _ _
â(1/6) = â1 / â6 â6 is the denominator but denom. . must be a whole number
_ _ _ _
â1 x â6 / â6 x â6 eliminate root 6 by multiplying _ . _ both numer. and denom. by â6
. you get â6 / 6 which should be the answer
2007-02-02 04:11:07 · answer #3 · answered by Pure 2 · 0⤊ 0⤋
square root of (x/y)= square root of (x)/square root of (y)
2007-02-02 01:45:30 · answer #4 · answered by Pradeep Chelani 2 · 0⤊ 0⤋