The 24 lines of longitude that approximates the 24 standard time zones are equally spaced around the equator.
The radius of the equator is about 3960 miles. About how wide (in miles) is each time zone at the equator?
2007-02-01 16:26:11 · 6 answers · asked by xiuhcoatl 1 in Science & Mathematics ➔ Mathematics
The circumference of a circle is 2*PI*radius, where PI = 3.1415. So the circumference of the earth at the equator is 2*3.1415*3960 = 24881 miles (rounding of to the nearest mile). So the meridians are spaced at a distance of 24881/24 = 1037 miles.
Why is this answer wrong? Maybe you need to carry it out to more decimal places.
PI = 3.1415926 ....
Distance between meridians = 2 * 3.1415926 * 3960 / 24 = 1036.73 .
I can't imagine why 1037 is incorrect, unless maybe the figure for the radius of the earth is wrong.
2007-02-01 16:33:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If i m not wrong, the correct answer should be only half of your answer, that is, 518 miles.
Try drawing out a circle and divide it into 24 zone equally base on the length of the circumference, u are actually only using half the circumference of the circle to divide instead of a full circle.
Hope it could help.
2007-02-02 00:45:09 · answer #2 · answered by sleeping_beauty1976 2 · 0⤊ 1⤋
first you need to find the circumference. 2piR which is 24881.41382 miles. divide that by 24 and you get 1036.725576 miles. So you are right. If your teacher says its wrong, then she's a dumbass
2007-02-02 00:33:42 · answer #3 · answered by John Doe 2 · 0⤊ 0⤋
3960 • 2Ï / 24 = 330Ï = 1036.73 mi.
2007-02-02 00:31:47 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
7920/24 = 330, making the answer 330pi. This rounds out to your answer, and you're never going to get it exact, so I can't see what's wrong.
2007-02-02 12:24:28 · answer #5 · answered by obelix 6 · 0⤊ 0⤋
u r right.................. believe urself
2007-02-02 00:50:12 · answer #6 · answered by Pradeep Chelani 2 · 1⤊ 0⤋