Algebra I math problem. Needs help extremely fast!?

Question

How do you turn Y-4=1/3(x-7) into slope intercept form. PLEASE show work.

Answer 1

The slope-intercept form is y = mx + b...

First: eliminate parenthesis - distribute the outer term with terms in the parenthesis...

y - 4 = (1/3)(x) - (1/3)(7)

Sec: combine the terms...

y - 4 = (1/3)x - 7/3

Third: isolate "y" on one side --- add "4" to both sides...

y - 4 + 4 = (1/3)x - 7/3 + 4

y = (1/3)x + 5/3

Answer 2

The equation for the slope intercept is:
y = mx + b
Where:
m = slope
b = y intercept
Solution:
y - 4 = 1/3 (x - 7)
Step One:
Use distributive law to remove the parenthetical expression;
y - 4 = (1/3)(x) - (1/3)(7)
Step Two:
Add +4 to both sides of the equation and perform algebraic addition;
y -4 + 4 = (1/3)(x) - (1/3)(7) + 4
y + 0 = (1/3)(x) - (1/3)(7) + 4
Step Three:
Add the whole number and the fraction together;
Since 4 = (1/3)(12)
y = (1/3)(x) - (1/3)(7) + (1/3)(12)
Step Four:
Factoring (numerical expression only);
y = (1/3)(x) + (1/3)(12 - 7)
Step Five:
Perform subtraction (numerical expression only);
y = (1/3)(x) + (1/3)(5)
Final form of the equation according to the problem:
y = (1/3)x + 5/3
Therefore the slope is 1/3 and the y-intercept is 5/3
Good luck!
May you have a peace of mind now.

Answer 3

The slope intercept form is y = mx + b, where m is the slope and b is the y intercept.

Thus, you need to convert your given equation to just
y = something
Add 4 on both sides then distribute the coefficient 1/3

y = x/3 - 7/3 +4 but 4 can be written as fraction = +12/3

y = x/3 +5/3

so your slope is 1/3 and intercept of +5/3

Answer 4

slope intercept form is y = mx + b

you are given

y+a = k(x+c), where a=-4, k=1/3, c=-7

first expand the right side by multiplying by k:
y+a = kx + kc
now subtract a from both sides of the equation
y = kx + kc - a

now slope (m) is k, and intercept (b) is kc-a
plug in the values and simplify
y = (1/3)x + (-7/3 + 4) = (1/3)x + (-7/3 + 12/3) = (1/3)x + 5/3

Answer 5

Well I'm not going to answer your problem for you, but a little help...
Solve it into slope intercept form. Slope intercept form is y=mx+b
Right now you have a y, an x, and an m (m=1/3 your slope). Really all you have to do is distribute your slope and move your 4 away from the y. make the problem look like y=mx+b

Answer 6

All of the above answers are correct. I would add that you if you are having a problem because of the fraction 1/3 multiply both sides by 3 to get rid of it.

This would give you 3y-12=x-7.

When you bring the 12 over you would have been left with 3Y=X+5.

Because you want to isolate y you would have to divide both sides by 3. This would give you y=x/3+5/3.

Answer 7

Y-4=1/3(x-7) distribute 1/3
y-4=x/3-7/3 add 4 to each side
y=x/3+4-7/3 get LCD in order to combine like terms
y=x/3+12/3-7/3
y=x/3+5/3
m=1/3
b=5/3

Answer 8

y = (1/3)x - (7/3) + 4
= (1/3)x + (5/3)

Answer 9

y-4=1/3(x-7) First you get rid of the parenthesis. so y-4=1/3x-7/3 Then you move the four to the other side by adding so you get y=1/3x + 5/3 and that is the answer.

Answer 10

slope intercept form is y = mx + b, so solve for y

y-4=1/3(x-7)
y-4=x/3-7/3
y=x/3-7/3+4
y=x/3-7/3+12/3
y=x/3+5/3
y=1/3x+5/3