(6-√8)(6-√8)
i think i calculated it wrong because i got 6-2-2-2-2
2007-02-01 15:57:13 · 4 answers · asked by ,,,,,,, 2 in Science & Mathematics ➔ Mathematics
First: use the Foiling Method....
(6)(6) + (6)(-V`8) + (-V`8)(6) + (-V`8)(-V`8)
Sec: combine the terms...
36 + (-6V`8) + (-6V`8) + (V`64)
36 - 6V`8 - 6V`8 + V`64
36 - 12V`8 + V`64
Third: find the square root of "8" & "64" > express the values in lowest terms....
36 - 12V`(4*2) + V`(8*8)
36 - 12V`(2*2*2) + 8
36 - 12(2)V`(2) + 8
36 - 24V`(2) + 8
36 + 8 - 24V`(2)
44 - 24V`(2)
2007-02-01 17:42:56 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
(6 - â8)(6 - â8)
= (6)(6) - (â8)(6) - (â8)(6) + (â8)(â8)
= 36 -12â8 + 8
= 44 - 24â2
2007-02-02 00:13:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
What you'll want to do is factor this bad boy. Remember FOIL.
So it'll be (6*6) + (6*-sqrt8) +(6*-sqrt8) + (-sqrt8*-sqrt8)
6*6 is 36, -sqrt8 * -sqrt8 is going to be 8. So you have 36 + 8 + 2(6*-sqrt8)
Which simplifies to 44 + 12*-sqrt8
2007-02-02 00:07:11 · answer #3 · answered by Nathan 2 · 0⤊ 0⤋
Use the FOIL method (First, Outside, Inside, Last).
(6*6) + (-6sqrt8) + (-6sqrt8) + (sqrt8*sqrt8)
36 - 12sqrt8 + 8
44 - 24sqrt2, which is about 10.06
2007-02-02 00:08:12 · answer #4 · answered by lango77 3 · 0⤊ 0⤋