could tell me how to do
find the x and y interspets for y= -6x-1
i dont get it please help
2007-02-01 15:54:46 · 10 answers · asked by °The Earth Goddess° 4 in Science & Mathematics ➔ Mathematics
1. find the x-intercept...
First: replace "0" with the y-variable in the equation...
0 = - 6x - 1
Sec: add "1" to both sides...
0 + 1 = - 6x - 1 + 1
1 = - 6x
- 6x = 1
Third: isolate "x" on one side --- divide both terms by "-6"...
- 6x/-6 = 1/-6
x = -1/6
Solution: (-1/6, 0)
2. find the y-intercept...
First: replace "0 with the x-variable in the equation...
y = - 6(0) - 1
y = 0 - 1
y = -1
Solution: (0, -1)
The x-intercept is (-1/6, 0) & the y-intercept is (0, -1)
2007-02-01 16:01:01 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
First of all, when you have an equation that you have given, where y=-6x-1, then the only intercept you are looking for is the y intercept. Same with if x=-6y-1, then you will be solving for the x intercept.
To find the intercept, think of the problem as y=mx + b, where as m=slope, and b=intercept. So for your problem, the y-intercept would be -1. Now if you set up the equation to solve for x, then your equation would be: x=-1/6y – 1/6, so the x-intercept would be -1/6.
Did that help?
2007-02-02 00:09:16 · answer #2 · answered by hpage 3 · 0⤊ 0⤋
You just need to solve the equation for y=0 (the x-intercept) and x=0 (the y-intercept). Just plug those values into the equation and you get:
0=-6x-1
1=-6x
-1/6=x
y=6*0-1
y=-1
2007-02-01 23:58:35 · answer #3 · answered by Nathan 2 · 0⤊ 0⤋
Your graph of y=-6x-1 intersepts the x axis when y=0, therefore because y=-6x-1, -6x-1=0. Now solve for x by
first adding 1 to bothe sides: -6x-1+(1)=0+(1)
note: -1+1=0
next divide by -6 to both sides: x=1/-6
that is your y intersept.
the x intersept is just your y value that your function produces when your x=0, so substitute it in there (put a zero everywhere you see a x in your original equation). y=-6*(0)-1--> y=-1
you may have to lavble them as points.
2007-02-02 00:34:30 · answer #4 · answered by Michael M 4 · 0⤊ 0⤋
to find x and y intercepts think about where the equation would intercept the cordinate plane. For x intercepts all the y's equal zero. So plug zero into your equation for y. 0=-6x-1 and solve for x. For y intercepts all the x's equal zero. So plug zero into your equation for x. y=-6(0)-1 and solve for y. so x=-1/6 and y=-1
2007-02-01 23:59:22 · answer #5 · answered by Matt Y 2 · 0⤊ 0⤋
the value of y intersect is when x=0. So, y=-6(0)-1=-1. y intersect is -1.
The value of x- intersect is when y=0. So, 0=-6x-1. x= 1/6
I hope this helps.
2007-02-01 23:59:21 · answer #6 · answered by Juni Mccoy 3 · 0⤊ 0⤋
for x interspets put y=0 in aove equation
0= -6x-1
6x= -1
x= -1/6
for y interspets put x=0 in aove equation
y= -1
2007-02-02 00:38:34 · answer #7 · answered by Pradeep Chelani 2 · 0⤊ 0⤋
in y=mx+b format, the b is the y intercept, so it is (0,-1) to find x intercept, just plug 0 in for y and solve for x. turns out to be (-1/6,0)
2007-02-01 23:59:10 · answer #8 · answered by climberguy12 7 · 1⤊ 0⤋
To find x-ints and y-ints, simply set the other variable equal to 0, then solve for the other.
So to find x-ints, you would set y = 0 and then solve for x.
2007-02-01 23:58:10 · answer #9 · answered by AibohphobiA 4 · 1⤊ 0⤋
to find the x-intersept, set y equal to 0 and solve for x
to find the y-intersept, set x equal to 0 and solve for y
2007-02-01 23:59:40 · answer #10 · answered by Peach 2 · 0⤊ 0⤋