(√2+√5)(7√11-√8)
i know its algebra but what branch. thanks a bunch.
2007-02-01 15:34:03 · 5 answers · asked by ,,,,,,, 2 in Science & Mathematics ➔ Mathematics
It's radical arithmetic man, real radical! That doesn't mean it's some new, pathbreaking or revolutionary kind of arithmetic, rather that it's plain old arithmetic involving "radicals" or things like square root operations.
Sometimes, as with (sqrt 17 + sqrt 11)(sqrt 17 - sqrt 11), the answer is simple. The "difference of two squares" formula would tell you that this is simply 17 - 11 = 6.
(That's because (a + b)(a - b) = a^2 - b^2 ; I just made the ' a ' and ' b ' equal to the relevant square root.)
However, in general you can't get rid of or combine the separate radicals completely, if at all. In your example, just one simplification is possible in the final product : the sqrt 2 and the - sqrt 8 combine to give you - sqrt 16 = - 4. But you'd still be left with three ugly radicals in the final expansion.
Live long and prosper.
2007-02-01 15:40:27 · answer #1 · answered by Dr Spock 6 · 2⤊ 0⤋
Nowadays these square roots and similar quantities are called "radicals", as other answerers have said. This is from the Latin word for a root.
Older mathematics books call them "surds". This is from the Latin or French word for "deaf". It was because such numbers seemed to be deaf to all your attempts to simplify them.
2007-02-02 07:13:42 · answer #2 · answered by bh8153 7 · 0⤊ 0⤋
It's not even algebra (there are no variables there). It's just arithmatic (with radicals). I wouldn't even call it math (just as I wouldn't call reciting the alphabet "literature").
2007-02-01 23:38:44 · answer #3 · answered by Andrew 6 · 4⤊ 0⤋
multiplying and adding and subtracting radicals, I guess
2007-02-01 23:40:30 · answer #4 · answered by Anonymous · 1⤊ 0⤋
actually it is aritmethic, and it uses radicals
2007-02-01 23:46:32 · answer #5 · answered by Anonymous · 1⤊ 0⤋