solve the equation x^2+26x+168
my answer is {12,14} am i right? thankssss
2007-02-01 14:46:21 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
0 i guess i am not sure it's just like that
2007-02-01 14:52:20 · update #1
First: factor the equation - multiply the 1st & 3rd coefficient to get "168." Find two numbers that give you "168" when multiplied & "26" (2nd/middle coefficient) when added/subtracted. The numbers are: "12 & 14"...
Sec: rewrite the expression with the new middle coefficients...
x^2 + 12x + 14x + 168
Third: when you have 4 terms - group "like" terms...
(x^2 + 12x) + (14x + 168)
*Factor both sets of parenthesis - find the least common factors...
x(x + 12) + 14(x + 12)
(x+12)(x+14)
P.S. The x-variable doesn't equal any number because, the expression is not an equation (set to equal "0").
2007-02-01 14:56:29 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Your signs are wrong both 12 and 14 should be minus {-12,-14} if you mean to say that x^2+26x+168 = 0
I think that is the equation you are talking about.
(otherwise, without an equal sign, you don't show an equality so you wouldn't have an equation)
2007-02-01 23:05:15 · answer #2 · answered by Other 3 · 0⤊ 0⤋
That is not an equation.
An equation has to *equal* something.
x^2+26x+168 = *what*???
If we assume you mean
x^2+26x+168 = 0
Factor: (x+12)(x+14)=0
So, the roots are -12, -14
Done.
2007-02-01 22:49:53 · answer #3 · answered by Jerry P 6 · 0⤊ 0⤋