this is the question:
"Suppose you are measuring the pressure inside a sealed cabinet using an open ended manometer, The atmospheric pressure is 762.4 mm Hg. If the mercury level on the side open to the atmosphere is 3.6 mm higher than on the side attached to the cabinet, what is the pressure inside the cabinet in units of kPa?"
Could you tell me how to work out this problem
2007-02-01 14:40:42 · 1 answers · asked by a.h. 2 in Science & Mathematics ➔ Chemistry
The pressure in the cabinet is higher than atmospheric pressure since it "pushed" the Hg toward the open end. Add the difference in heights to the atmospheric pressure to get the pressure inside the cabinet.
762.4 mm + 3.6 mm = 766.0 mm Hg
Use dimensional analysis to change from mm Hg to kPa
760 mm Hg = 101.4 kPa
(766.0 mm Hg / 760 mm Hg) X 101.4 kPa = answer
2007-02-01 14:51:32 · answer #1 · answered by physandchemteach 7 · 0⤊ 0⤋