what mass of sulfuric acid, H2SO4, is required to react with 1.27g of KOH?...see details for more information

Question

the prodicts of this reaction are K2SO4, and water.
H2SO4 + 2KOH > K2SO4 + 2H2O

Answer 1

1.27 g KOH / 56 g/mol = 0.0227 moles KOH

2 moles of KOH react with 1 mole of H2SO4, so the amount of sulfuric is half of the KOH, or 0.0114 moles (with rounding).

0.0114 moles * 98 g/mol = 1.11 g H2SO4