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The problem goes as follows--- " A car can travel 11 km for every liter(L) of gas it uses (26 mi/gal). If the driver's average speed is 28 km/h (18 mi/h), how many hours can the driver travel before emptying a full 35 L gas tank." I have to show work, so please don't just answer the question. If possible, please explain what I need to do.

2007-02-01 14:26:23 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

THANKS YOU SOOO MUCH.

2007-02-01 14:40:13 · update #1

11 answers

There is nothing complicated about this problem. The only trick is to make sure you do your calculations with consistent units.

So taking km and L (forgetting the Miles and Gallons), basically the car can travel 11km every 1 Liter. So since the car has 35 Liters, it can travel for 35 x 11 km. (= 385km) Since the speed is 28km/h, the time it takes to travel 385km is 385/28 = 13.75 or 3h 45min.

Do you see the logic? (also remember speed = distance / time so time = distance / speed)

So now write this step by step showing your work.

Well, don't forget the driver might need to take atleast a 10min bathroom break in reality :D

2007-02-01 14:38:26 · answer #1 · answered by kevinrtx 5 · 0 0

The distance will be equal to the size of the tank times the mileage (kilometerage?) per liter, so it can go 11 X 35 or 385 km.

If the driver's average speed is 28 km/h, then it will take him 385/28 or 13.75 hours to empty the tank.

2007-02-01 14:31:16 · answer #2 · answered by TheOnlyBeldin 7 · 0 0

n=1

2016-05-24 04:03:33 · answer #3 · answered by Anonymous · 0 0

11 km/L with 35 Liters
Multiply 11*35 (Liters cancel out) = 385
To multiply two digit numbers by 11 add the two digits (3+5=8) and put it in the middle of the two digits, it always works, it's just a trick.
28km/h - Average Speed
Divide 385 Km by 28km/h, kilometers cancel out and you get 1/1/h which equals hours.
385/28=13.75 hours, or 13 hours and 45 minutes.

2007-02-01 14:32:04 · answer #4 · answered by Anonymous · 0 0

If you travel 11 km/L, then after 35 L, you have traveled 11*35 km = 385 km. If you're going 28 km/hr, and you're traveling for 385 km, then your time traveled will be 385/28 = 13.75 m

2007-02-01 14:31:26 · answer #5 · answered by J 2 · 0 0

ok let's just work in km/h and km/L ignore the miles and gallons

given: 11km per 1 L = 11 km/L
v = 28 km/h
V = 35L

first, find the km's driven for the volume of the gas tank:

d = (11 km/L)(35L)
= 385 km

then you can figure out time using t = d/v
t = (385km) / (28km/h)
= 13.75 hours
= 13 hours, 45 minutes

2007-02-01 14:32:49 · answer #6 · answered by Anonymous · 0 0

11km for every liter with a 35 liter fuel capacity.

11 km/L x 35 L = 385 km on a full tank. (the liter units cancel out)

385 km / 28 km/hr = 13.75 hours on a full tank. (the km units cancel out)

I think..., its a bit late here but I think thats right.

2007-02-01 14:34:59 · answer #7 · answered by Bob 3 · 0 0

Try it like this.
The driver starts with 35 L of gas.
She travels 11 km, and uses 1 L of gas.

So ... multiply the numbers by 10 ... you get this:
She travels 110 km, and uses 10 L of gas.

What would you have to multiply by, to get this:
She travels km, and uses 35 L of gas.
When you solve that part, you know how far she can go.

Now for the second part.
She travels for 1 hour, and goes 28 km.

So ... multiply the numbers by 10 ... you get this:
She travels for 10 hours, and goes 280 km.

Now take the number#1 from the first part.
What would you have to multiply by, to get this:
She travels for hours, and goes km.

2007-02-01 14:37:13 · answer #8 · answered by morningfoxnorth 6 · 0 0

35 L*11 km/L or 385 km

so at 28 km/hr, divide 385 km/ (28km/hr) or 13.75 hours

2007-02-01 14:31:15 · answer #9 · answered by leo 6 · 0 0

11 L X 35 L = 385KM Divided by 28KM/hr = 13.75 Hours

2007-02-01 14:32:16 · answer #10 · answered by bob shark 7 · 0 0

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