Using binary, 11 would be 1011, what would it be in base 13?
2007-02-01 14:18:43 · 9 answers · asked by Bob B 2 in Science & Mathematics ➔ Mathematics
0B (base 13) = 11 (base 10)
Let's count in base 13
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, 10
2007-02-01 14:23:48 · answer #1 · answered by Thomas K 6 · 0⤊ 0⤋
Since there are only 10 digits but base 13 would need 13, it uses A for 10, B for 11 and C for 12.
2007-02-01 14:22:35 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
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2016-05-24 04:02:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
B
In hexidecimal (base 16), the convention is to use A through F
to represent 10 through 15, so in base 13, you should use
A through C.
2007-02-01 14:23:32 · answer #4 · answered by Andrew 6 · 0⤊ 0⤋
It is undefined. First, you need to pick out single-digit symbols for the quantities 10, 11, and 12. And any truly serious definition would NOT include letters of the alphabet, to avoid confusion. Best of luck.
2007-02-01 14:21:44 · answer #5 · answered by Dorothy and Toto 5 · 0⤊ 0⤋
The numbers won't change until after 9
10 = A
11 = B
12 = C
13 = 10
2007-02-01 14:22:45 · answer #6 · answered by davidosterberg1 6 · 0⤊ 0⤋
In base 13, 11 would be B.
The numbers are 1,2,3,4,5,6,7,8,9,A,B,C
After that is 10, which is the same as 13base10.
2007-02-01 14:22:10 · answer #7 · answered by Steve A 7 · 1⤊ 0⤋
I would say
"eleven in base thirteen"
(really, I do not know.)
2007-02-01 14:22:24 · answer #8 · answered by T Time 6 · 0⤊ 0⤋
Yes, it should be B
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2007-02-01 20:44:57 · answer #9 · answered by Anonymous · 0⤊ 0⤋