An automobile starts from rest and accelerates at 3m?s for 4 seconds. How fast is it going after the acceleration?
What formula do i use to figure this out?
Any help is appreciated.Thanks..
2007-02-01 13:08:55 · 4 answers · asked by angelgirl 2 in Science & Mathematics ➔ Physics
acceleration is change in velocity over time.
Change in velocity is acceleration times time.
Got it?
2007-02-01 13:13:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a = (v-u) / t
where a = acceleration 3 ms^-2
v = final velocity to be found
u = initial velocity 0 ms^-1
t = time 4 s
at = v -u
v = u + at
substituting in the values.
v = 0 ms^-1 + (3 ms^-2 x 4 s)
v = 12 ms^-1
2007-02-02 07:48:23 · answer #2 · answered by lenpol7 7 · 0⤊ 0⤋
i think its 12 m/s. Cos after 1 second its going 3m/s and so on. Actually, doesn'y acceleration get measured in m/s/s. Thus the vehicle accelerates by 3 m/s every second. Thats a hard one, i'd have to spend a bit of time on it. i think, sos.
2007-02-01 13:14:07 · answer #3 · answered by smudgeuk9 3 · 0⤊ 0⤋
The formula you use is v(t) = v0(t) + at
Since the "start" is "rest", that means v0(t) = 0.
So v(t) = at, or 3*4, which is 12 m/s
2007-02-01 13:12:04 · answer #4 · answered by firefly 6 · 0⤊ 0⤋