Find the height of a triangle that has an area of 20 m^2 n^5 and a base of 10 m n^2.?

Question

and.....

Calculate the area of a rectangle that has a width that measures 10s^4t and a length of 40s^3t.


thank you

Answer 1

1. A = bh/2
=> 20 m^2 n^5 = 10 m n^2 h / 2
=> h = 20 m^2 n^5 * 2 / (10 m n^2)
= 4 (m^2 / m) (n^5/ n^2)
= 4 m n^3.

2. A = w.l = (10 s^4 t) (40 s^3 t)
= 400 s^7 t^2.