The question is:
What is the probability that a carrier and a person who has a sex-linked genetic disorder willhave a son with the disorder? A daughter? Use a Punnett square to answer these questions.
I'm guessing the carrier is a carrier of the sex-linked genetic disorder.
So how do I do this?
2007-02-01 12:59:31 · 5 answers · asked by . v a l e r i e . 2 in Education & Reference ➔ Homework Help
You guys have really helped!! I didn't really understand how this stuff worked but now I do! Thanks to ALL of you guys gor helping me understand How Genes on Sex Chromosomes are Inherited!!!
2007-02-01 13:09:59 · update #1
The sex-linked disorder is on the X. It has to be a recessive disorder for carriers to be possible.
So the allele for the disorder is b and the normal alleles is B.
Mom is a carrier XB Xb Dad has the disorder Xb Y
Put the gametes from these parents on a Punnett square.
Sons will turn out to be XB Y or Xb Y which is 1/2 chance of having the disorder.
Daughters will turn out to be XB Xb or Xb Xb which is 1/2 chance of having the disorder, as well.
2007-02-01 13:06:21 · answer #1 · answered by ecolink 7 · 0⤊ 0⤋
the punett square would look kinda like this i think t t
T Tt Tt
t tt tt
but like i said i THINK im not sure but this is what im working on right nowand we would say the lower case is the sex-linked disease so it would be a 50% chance the daughter will get it and a 100% chance the son would get it (aww too bad) so dont hold me accountable if im wrong but i think this is right
2007-02-01 21:10:59 · answer #2 · answered by zdudeb 2 · 0⤊ 0⤋
learn how to use the punnett square, it isn't that hard.
2007-02-01 21:06:10 · answer #3 · answered by sarah c 2 · 0⤊ 0⤋
i have no clue you should ask your science teacher and you confused the best out of me..!!!????
2007-02-01 21:03:53 · answer #4 · answered by Vanessa B 1 · 0⤊ 0⤋
just fo with wat up think ur teacher sould give u credit for trying..
2007-02-01 21:03:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋