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do you take ln or do you just subtract a one

2007-02-01 12:38:31 · 4 answers · asked by kruk189 1 in Science & Mathematics Mathematics

4 answers

Im assuming you mean x^e^x?

if so you take the natural log of both sides and then differentiate both sides. The answer will end up being (e^x*ln(x) + (e^x)/x)*x^e^x

If you did indeed mean x^e^1

Then you would just do the basic power rule.. resulting in
e*x^(e-1)

2007-02-01 12:44:23 · answer #1 · answered by smawtadanyew 2 · 0 1

e is a constant like 2 or 3, so derivative of x^e is just ex^(e-1).

2007-02-01 20:45:02 · answer #2 · answered by Philo 7 · 0 0

it is e*x^(e-1)

2007-02-03 08:48:34 · answer #3 · answered by santmann2002 7 · 0 0

ex^(e-1)

2007-02-01 20:44:00 · answer #4 · answered by leo 6 · 0 0

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