"The wheels on a toy car have a diameter of 2 inches and are revolving at 1440 radians per minute. What is the linear velocity of the toy car in feet per second?"
I've figured out that the circumference of the circle is 6.28 inches...and then I have no idea where to go from there. Help, please?
2007-02-01 12:26:02 · 2 answers · asked by Aliza, Queen of the Night 3 in Science & Mathematics ➔ Mathematics
1 revolution = 2*PI radians so 1440 radians/min = 1440/(2*PI) r.p.m.=720/PI r.p.m. divided by 60, 12/PI r.p.s.
Now v=12/PI r.p.s. 2*PI*2 inches =48 inches/s.
2007-02-01 13:05:07 · answer #1 · answered by Juan C 2 · 0⤊ 0⤋
With a 1 inch radius the circumference is 2Ï inches. One full rotation of the wheel is 2Ï radians, so divide 1440 radians/min by 2Ï radians/rotation, get 720/Ï rotations/min, then multiply by 2Ï inches/rotation, get 1440 inches/min. multiply by 1 ft/ 12 in, get 120 ft/min. Finally, multiply by 1 min/ 60 sec, get 2 ft/s.
2007-02-01 13:05:39 · answer #2 · answered by Philo 7 · 0⤊ 0⤋