an 80 kg fighter pilot goes into a dive, accelerating downward at 22 meters per second squared. find the magnitude of the downward force that the back of the seat exerts on the pilot.
2007-02-01 12:14:59 · 6 answers · asked by argentina_mandy20 1 in Science & Mathematics ➔ Physics
The acceleration on the pilot comes from 2 sources:
1: gravity (10 m /s/s)
2: seat (? m/s/s)
These add up to 22 m/s/s.
Sove for the seat's contribution to acceleration.
Use F=ma to get the force.
Good luck!
2007-02-01 12:19:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
F=m(g-a),where a=downward acceleration
=80(10-22)
=-960N
So,the magnitude of force tht the back seat exerts on pilot is 960N.
2007-02-01 12:25:36 · answer #2 · answered by yan 2 · 0⤊ 0⤋
Start with Newton's second law:
Sum of the forces down - Sum of the forces up = ma
mg + Fseatback - 0 = ma
80(9.8) + Fseatback = 80(22)
F seatback = 976 N
2007-02-01 12:23:49 · answer #3 · answered by Dennis H 4 · 0⤊ 0⤋
damn quickly: Impulse-momentum equation: F * t = m * change in velocity F = 111,563 N - 400 N = 111,163 N 111,163 N * 4.1743 sec = 20.418 kg * V 464028 N/s = 20.418 kg * V V = 464028 N/s / 20.418 kg V = 22,726.4 m/s (the Newton is a derived from a kg*m/s^2 so contraptions cancel ideas-blowing to leave m/s)
2016-12-03 08:22:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Before enabling you with your homework, I would just as soon that you knew the difference between 'smart' and 'capable'!
LOOK THESE WORDS UP!!!
2007-02-01 12:23:58 · answer #5 · answered by Anonymous · 0⤊ 0⤋
960N
2007-02-01 12:45:38 · answer #6 · answered by futureastronaut1 3 · 0⤊ 0⤋