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1.30 kilograms of water at 11.0C is placed on a heat source. The water's temperature is raised to 61.0C. How much heat is absorbed by the water?

How do you solve this?

2007-02-01 11:36:19 · 2 answers · asked by Lemonade is Good 5 in Science & Mathematics Physics

2 answers

specific heat of water times mass of water times difference in temperature

2007-02-01 11:40:45 · answer #1 · answered by astatine 5 · 1 0

Heat absorbed by water, Q=mcT,where m=mass of water
c=specific heat of water
T=temperature changed
So,Q=1.30x4.2x(61.0-11.0)
=273J

2007-02-01 19:57:26 · answer #2 · answered by yan 2 · 1 1

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