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If you fill a bath to the brim with yourself in it, would an identical bath with someone half your physical size, also filled to the brim, weigh the same as your own bath? Half my friends say yes and half say no!

2007-02-01 11:34:22 · 5 answers · asked by Anonymous in Science & Mathematics Other - Science

5 answers

Check out the Principle of Archimedes.

It depends on the density of the object in the water.

A more dense object, like muscle, will dispace less water, nearing the equiv to the volume of the object.

A less dense object like fat will displace water equal to the weight of the object, and displace the weight of the object.

Of course the extremes are floating to the top (least dense) and sinking like a stone (most dense).

2007-02-01 11:44:59 · answer #1 · answered by strayinma 4 · 0 0

Are you weighing the bath with the persons in the bath, or not?
Also can we assume that the person of half physical size is half the weight AND half the volume of water displaced, but they are not floating in the water.
You need to define the problem more tightly before your question can be answered properly.

2007-02-01 19:47:15 · answer #2 · answered by Anonymous · 0 0

Simple answer, No. your bath would be heavier.
Without using scientific works and boring formula's. If you float in the bath the water that spills out will weigh the same as you. If you sink the water that spills out would be the same amount as it would take to fill your body.

2007-02-01 22:16:10 · answer #3 · answered by sundayman 1 · 0 0

Humans are less dense than water (dead bodies float). Therefore the bath with less human and more water will be heavier. The bath with the half-sized human will weigh more.

2007-02-01 19:47:50 · answer #4 · answered by Wing commander 3 · 0 0

no, the human body and water have defferent specific gravities / densities ( 1 cubic foot of water weighs differend than 1 cubic foot of human body)

2007-02-01 19:42:40 · answer #5 · answered by jglende33 2 · 0 0

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