Energy & Temperature?

Question

Whats the amount of energy needed to raise 18kg of cooper from 35°C to 60°C?

What temperature change would 2500 g of iron experience if 42,000 J of energy is added to it?

Answer 1

Sojsail is on the right track.
Indeed the magic equation is

Q=c m delta T

Q- heat in calories or kilocalories
c - specific heat capacity (see reference)
delta T- is the difference it temperature required to raise or drop from the original temperature.

For copper the specific heat capacity c= 0.385J/(gm K) (in degrees Kelvin however it is the same in degrees of Centigrade)

Q=0.385x18 000x(60-35)= 173250 Joules

For the second part of the problem

delta T= Q/(c m)
sice C(iron)= 0.450J/(g degK)
delta T=42000/( 0.450 x2500 )
finaly

delta T=37.3 deg K or deg C

Answer 2

You must have the specific heat of copper and iron. The units on the specific heat should tell you how to do it.

If not, Q = m*c*deltaT