A ball is dropped from 10 feet above the ground. It hits the ground and bounces up half as high a it fell.
a. what height doesthe ball reach on the fourth bounce?
b. Find the total distance up and down that the ball has traveled when it hits the ground the fifth time.
2007-02-01 09:35:37 · 6 answers · asked by springvalleyprincess 1 in Education & Reference ➔ Homework Help
Falls 10 feet
bounces to 5ft then falls 5ft
bounces to 2.5ft then falls 2.5ft
bounces 1.25 ft then falls 1.25 ft
bounces 0.75 feet then falls 0.75 ft
bounces 0.375 feet then falls 0.375 feet
A. 0.75 feet
B.10+5+5+2.5+2.5+1.25+1.25+
0.75+0.75=29.75 feet
2007-02-01 09:44:54 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First bounce it gets up to 5 feet.
Second bounce it gets up to 2.5 feet.
Third bounce it gets up to 1.25 feet.
Fourth bounce it gets up to 0.625 feet.
The ball would have traveled 10 feet when it hits the ground the first time, 20 feet when it hits the second time, 25 feet when it hits the third time, 27.5 feet when it hits the fourth time, and 28.75 feet when it hits the ground the fifth time.
2007-02-01 09:51:11 · answer #2 · answered by Elisa 4 · 0⤊ 0⤋
a. 1.25 ft
b. 11.42 ft
The balls momentum is going to decrease with every bounce by 50%:
10*.5/y=x
y= # of bounces
x= height of ball per bounce
2007-02-01 09:43:32 · answer #3 · answered by red 2 · 0⤊ 0⤋
um...this is what I think it is:
a. 1/2 (10) = 5 x 4 = 20 ft
b. 1/2 (10) = 5 x 5 = 25 ft
2007-02-01 09:40:38 · answer #4 · answered by Dee 6 · 0⤊ 0⤋
a .65 feet
b 28.85 feet
2007-02-01 10:34:03 · answer #5 · answered by leftyjohnthegodofgames 2 · 0⤊ 0⤋
a. 0.5 ft
b. 18 ft
2007-02-01 09:39:54 · answer #6 · answered by TKM2001 2 · 0⤊ 0⤋