question down bellow?

Question

(a) How many seconds does it take a 25.0-hp motor to lift a 1700-lb elevator a distance of 70.0 ft? ____s
(b) What was the average velocity of the elavator? ____ft/s

Answer 1

Your first answer needs a 1/x

Work to be done = 1700*70 ft-lbs = 119k ft-lbs

Power in ft-lbs/min = 25 hp * 33k ft-lbs/min / hp = 825k ft-lbs/min

So that elevator can do 825 ft-lbs of work in a minute. So that elevator can do this small job in
119k/825k minutes = .144 minutes.

Answer 2

That is going to be one fast elevator are you sure you are not making a roller coaster